University Maths Notes: Calculus – The Mean Value Theorem – A Summary
If
is
a differentiable function with a continuous derivative and if
are
any two points then there is a point
between
and
at
which
f'(c) =
This result is also `geometrically obvious' once you draw the picture.
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Mean Value Theorem:
somewhere between a and b, the graph must be parallel
to the chord![]()
The expression
is
just the slope of the chord
So
the theorem is saying that there must be a point
between
and
at
which the slope of the graph is equal to the slope of the chord![]()
This may seem very simple--it is very simple--but it is also very important. In most of its applications we think of the result in the following way, which is easily derived.
![]()
(Note that the theorem does not tell us what c is--just that it must be there.)
Here's a simple application of this theorem. Suppose
that
between
and
Then
must
be positive (whatever c is). So
must
be bigger than
So,
in an obvious sense, the function must be increasing.
Here's another typical application. Let
Then
So
we must have
This
result is rubbish. For example, tan(
)
= tan(0) = 0. But 0 - 0 is not bigger than
- 0. What's gone wrong?
The problem here is that
is
not a differentiable function between 0 and
--it
blows up at
When
using these theorems, no matter how `obvious' they are, you really
must check that the conditions of the theorem are precisely
satisfied.