A Level Maths Notes: FP1 – Solving Second Order Linear Non - Homogeneous Differential Equations
Any differential equation of the form
(1)
is a second order differential equations and there is a standard
technique for solving any equation of this sort. We solve the
homogeneous equation
(2)
first for the 'complementary' solution
We
assume a solution of the form
and
substitute this into (2). We extract the non zero factor – since no
exponential is zero for any finite x -
to
obtain a quadratic equation. We solve this equation to obtain
solutions
and
and
then the general solution is
Having
found the complementary solution
we
now find a particular solution
to
(1) by assuming a solution 'similar' to
then
the general solution to (1) is given by![]()
Example: Solve the equation
(2)
subject to
and
at![]()
![]()
Substitution of the above expressions into
gives![]()
We can factor out the nonzero
to
obtain![]()
Because
is
non zero we can divide by it to obtain
and
we factorise this expression to obtain
and
solve to obtain
and
The
complementary solution is then
![]()
To find a particular solution we assume
since
is
a polynomial of degree one.
and
Substitute
these into (1)
![]()
Equating coefficients of
gives![]()
Equating constants gives![]()
![]()
when
implies
(3)
at
implies
(4)
(3)+(4) gives
then
from (3)![]()
The solution is
![]()